Q.
In an examination, there are three multiple choice questions and each question has 4 choices. Number of ways in which a student can fail to get all answers correct is
14703
214
Permutations and Combinations
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Solution:
There are three multiple choice questions, each has four possible answers. Therefore, the total number of possible answers will be 4×4×4=64. Out of these possible answers only one will be correct and hence the number of ways in which a student can fail to get all correct answers is 64−1=63.