In an atom electrons revolves around the nucleus along a path of radius 0.72 mathringA making 9.4 × 1018 revolution per second. The equivalent current is (e = 1.6 × 10-19 C)

Question

In an atom electrons revolves around the nucleus along a path of radius 0.72 mathringA making 9.4 × 1018 revolution per second. The equivalent current is (e = 1.6 × 10-19 C) (A) 1.2 A (B) 1.5 A (C) 1.4 A (D) 1.8 A

Tardigrade Admin · Accepted Answer

Radius of electron orbit r=0.72 mathringA=0.72 × 10-10 m Frequency of revolution of electron in orbit of given atom upsilon=9.4 × 1018 rev/s (where T is time period of revolution of electron in orbit) ∴ Then equivalent current is I=(e/T)=e upsilon=1.6 × 10-19 × 9.4 × 1018 =1.504 A

Q. In an atom electrons revolves around the nucleus along a path of radius $0.72 \overset{˚}{A}$ making $9.4 \times 1 0^{18}$ revolution per second. The equivalent current is $(e = 1.6 \times 1 0^{- 19} C)$

$1.2 A$

$1.5 A$

$1.4 A$

$1.8 A$

Q. In an atom electrons revolves around the nucleus along a path of radius 0.72A˚ making 9.4×1018 revolution per second. The equivalent current is (e=1.6×10−19C)

1.2A

1.5A

1.4A

1.8A

Radius of electron orbit r=0.72A˚=0.72×10−10m Frequency of revolution of electron in orbit of given atom υ=9.4×1018 rev/s (where T is time period of revolution of electron in orbit) ∴ Then equivalent current is I=Te​=eυ=1.6×10−19×9.4×1018 =1.504A

Q. In an atom electrons revolves around the nucleus along a path of radius $0.72 \overset{˚}{A}$ making $9.4 \times 1 0^{18}$ revolution per second. The equivalent current is $(e = 1.6 \times 1 0^{- 19} C)$

$1.2 A$

$1.5 A$

$1.4 A$

$1.8 A$