In an atom bomb, a temperature of about 10 million degree is developed at the moment of explosion. In what region of At spectrum do the wavelength corresponding to maximum energy density lie, if the light source is in the atom bomb?

Question

In an atom bomb, a temperature of about 10 million degree is developed at the moment of explosion. In what region of At spectrum do the wavelength corresponding to maximum energy density lie, if the light source is in the atom bomb? (A) Ultraviolet region (B) Visible region (C) Infrared region (D) X-ray region

Tardigrade Admin · Accepted Answer

From Weins law, λ mT= constant =0.3× 10-2 λ m=(0.3× 10-2/T) =(0.3× 10-2/10× 106) =3 overset texto mathop textA

Q. In an atom bomb, a temperature of about 10 million degree is developed at the moment of explosion. In what region of At spectrum do the wavelength corresponding to maximum energy density lie, if the light source is in the atom bomb?

Ultraviolet region

Visible region

Infrared region

X-ray region

From Weins law, $λ_{m} T =$ constant $= 0.3 \times 10^{- 2}$ $λ_{m} = \frac{0.3 \times 10 ^{- 2}}{T}$ $= \frac{0.3 \times 10 ^{- 2}}{10 \times 10 ^{6}}$ $= 3 A o$

Q. In an atom bomb, a temperature of about 10 million degree is developed at the moment of explosion. In what region of At spectrum do the wavelength corresponding to maximum energy density lie, if the light source is in the atom bomb?

Ultraviolet region

Visible region

Infrared region

X-ray region

From Weins law, λm​T= constant =0.3×10−2 λm​=T0.3×10−2​ =10×1060.3×10−2​ =3Ao

From Weins law, $λ_{m} T =$ constant $= 0.3 \times 10^{- 2}$ $λ_{m} = \frac{0.3 \times 10 ^{- 2}}{T}$ $= \frac{0.3 \times 10 ^{- 2}}{10 \times 10 ^{6}}$ $= 3 A o$