In an atom, an electron is moving with a speed of 600 m/s with a certainty of 0.005% with which the position of the electron can be located is (.h=6.6× 10- 34 kgm2s- 1 , mass of electron =9.1× 10- 31 kg ):

Question

In an atom, an electron is moving with a speed of 600 m/s with a certainty of 0.005% with which the position of the electron can be located is (.h=6.6× 10- 34 kgm2s- 1 , mass of electron =9.1× 10- 31 kg ): (A) 5.10× 10- 3 m (B) 1.92× 10- 3 m (C) 3.84× 10- 3 m (D) 1.52× 10- 3 m

Tardigrade Admin · Accepted Answer

Δ x.mΔ v=(h/4 π ) Δ x=(h/4 π m Δ v) Δ v=600× (0.005/100) Δ x=(6.625 × 1 0- 34/4 × 3.14 × 9.1 × 1 0- 31 × 0.03) =1.92× 10- 3 m

Q. In an atom, an electron is moving with a speed of 600 m/s with a certainty of 0.005% with which the position of the electron can be located is $(h = 6.6 \times 1 0^{- 34}$ $k g m^{2} s^{- 1}$ , mass of electron $= 9.1 \times 1 0^{- 31}$ $k g$ ):

$5.10 \times 1 0^{- 3}$ $m$

$1.92 \times 1 0^{- 3} m$

$3.84 \times 1 0^{- 3}$ $m$

$1.52 \times 1 0^{- 3}$ $m$

$Δ x . m Δ v = \frac{h}{4 π}$
$Δ x = \frac{h}{4 πm Δ v}$
$Δ v = 600 \times \frac{0.005}{100}$
$Δ x = \frac{6.625 \times 1 0 ^{- 34}}{4 \times 3.14 \times 9.1 \times 1 0 ^{- 31} \times 0.03}$
$= 1.92 \times 1 0^{- 3} m$

Q. In an atom, an electron is moving with a speed of 600 m/s with a certainty of 0.005% with which the position of the electron can be located is (h=6.6×10−34 kgm2s−1 , mass of electron =9.1×10−31 kg ):

5.10×10−3 m

1.92×10−3m

3.84×10−3 m

1.52×10−3 m