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Q. In an atom, an electron is moving with a speed of 600 m/s with a certainty of 0.005% with which the position of the electron can be located is $\left(\right.h=6.6\times 10^{- 34}$ $kgm^{2}s^{- 1}$ , mass of electron $=9.1\times 10^{- 31}$ $kg$ ):

NTA AbhyasNTA Abhyas 2022

Solution:

$\Delta x.m\Delta v=\frac{h}{4 \pi }$
$\Delta x=\frac{h}{4 \pi m \Delta v}$
$\Delta v=600\times \frac{0.005}{100}$
$\Delta x=\frac{6.625 \times 1 0^{- 34}}{4 \times 3.14 \times 9.1 \times 1 0^{- 31} \times 0.03}$
$=1.92\times 10^{- 3 \, }m$