In an apparatus, the electric field was found to oscillate with an amplitude of 18 V/m . The magnitude of the oscillating magnetic field is

Question

In an apparatus, the electric field was found to oscillate with an amplitude of 18 V/m . The magnitude of the oscillating magnetic field is (A)  6× 10-8tesla  (B)  3× 10-8tesla  (C)  12× 10-8tesla  (D)  9× 10-8tesla

Tardigrade Admin · Accepted Answer

Amplitude of electric field E0=18 V/m The magnitude of the oscillating magnetic field E0=(E0/c)=(18/3× 108)=6× 10-8tesla

Q. In an apparatus, the electric field was found to oscillate with an amplitude of $18 V / m$ . The magnitude of the oscillating magnetic field is

$6 \times 10^{- 8} t es l a$

$3 \times 10^{- 8} t es l a$

$12 \times 10^{- 8} t es l a$

$9 \times 10^{- 8} t es l a$

Amplitude of electric field $E_{0} = 18 V / m$ The magnitude of the oscillating magnetic field $E_{0} = \frac{E _{0}}{c} = \frac{18}{3 \times 10 ^{8}} = 6 \times 10^{- 8} t es l a$

Q. In an apparatus, the electric field was found to oscillate with an amplitude of 18V/m . The magnitude of the oscillating magnetic field is

6×10−8tesla

3×10−8tesla

12×10−8tesla

9×10−8tesla