Question

In an apparatus, the electric field was found to oscillate with an amplitude of $ 18\,\,V/m $ . The magnitude of the oscillating magnetic field is

• A. $ 6\times {{10}^{-8}}tesla $
• B. $ 3\times {{10}^{-8}}tesla $
• C. $ 12\times {{10}^{-8}}tesla $
• D. $ 9\times {{10}^{-8}}tesla $

Answer 1

Answer: (A)

Amplitude of electric field $ {{E}_{0}}=18\,\,V/m $ The magnitude of the oscillating magnetic field $ {{E}_{0}}=\frac{{{E}_{0}}}{c}=\frac{18}{3\times {{10}^{8}}}=6\times {{10}^{-8}}tesla $