In an apparatus, the electric field was found to oscillate with an amplitude of 18 V / m. The magnitude of the oscillating magnetic field will be

Question

In an apparatus, the electric field was found to oscillate with an amplitude of 18 V / m. The magnitude of the oscillating magnetic field will be (A) 4 × 10-6 T (B) 6 × 10-8 T (C) 9 × 10-9 T (D) 11 × 10-11 T

Tardigrade Admin · Accepted Answer

c=(E/B) ⇒ B=(E/c) =(18/3 × 108)=6 × 10-8 T

Q. In an apparatus, the electric field was found to oscillate with an amplitude of $18 V / m$ . The magnitude of the oscillating magnetic field will be

$4 \times 1 0^{- 6} T$

$6 \times 1 0^{- 8} T$

$9 \times 1 0^{- 9} T$

$11 \times 1 0^{- 11} T$

$c = \frac{E}{B} \Rightarrow B = \frac{E}{c}$
$= \frac{18}{3 \times 1 0 ^{8}} = 6 \times 1 0^{- 8} T$

Q. In an apparatus, the electric field was found to oscillate with an amplitude of 18V/m. The magnitude of the oscillating magnetic field will be

4×10−6T

6×10−8T

9×10−9T

11×10−11T