Question

In an apparatus, the electric field was found to oscillate with an amplitude of $18\, V / m$. The magnitude of the oscillating magnetic field will be

• A. $4 \times 10^{-6} T$
• B. $6 \times 10^{-8} T$
• C. $9 \times 10^{-9} T$
• D. $11 \times 10^{-11} T$

Answer 1

Answer: (B)

$c=\frac{E}{B} \Rightarrow B=\frac{E}{c}$
$=\frac{18}{3 \times 10^{8}}=6 \times 10^{-8} T$