In an α-decay, the kinetic energy of α particle is 48 MeV and Q value of the reaction is 50 MeV. The mass number of the mother nucleus is (Assume that daughter nucleus is in ground state)

Question

In an α-decay, the kinetic energy of α particle is 48 MeV and Q value of the reaction is 50 MeV. The mass number of the mother nucleus is (Assume that daughter nucleus is in ground state) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

We have, Kα=(my/my+mα) ⋅ Q ⇒ Kα=(A-4/A) × Q ⇒ 48=(A-4/A) × 50 ⇒ A=100

Q. In an $α$ -decay, the kinetic energy of $α$ particle is $48 M e V$ and $Q$ value of the reaction is $50 M e V$ . The mass number of the mother nucleus is (Assume that daughter nucleus is in ground state)

We have, $K_{α} = \frac{m _{y}}{m _{y} + m _{α}} \cdot Q$
$\Rightarrow K_{α} = \frac{A - 4}{A} \times Q$
$\Rightarrow 48 = \frac{A - 4}{A} \times 50$
$\Rightarrow A = 100$

Q. In an α-decay, the kinetic energy of α particle is 48MeV and Q value of the reaction is 50MeV. The mass number of the mother nucleus is (Assume that daughter nucleus is in ground state)

We have, Kα​=my​+mα​my​​⋅Q ⇒Kα​=AA−4​×Q ⇒48=AA−4​×50 ⇒A=100

Q. In an $α$ -decay, the kinetic energy of $α$ particle is $48 M e V$ and $Q$ value of the reaction is $50 M e V$ . The mass number of the mother nucleus is (Assume that daughter nucleus is in ground state)

We have, $K_{α} = \frac{m _{y}}{m _{y} + m _{α}} \cdot Q$
$\Rightarrow K_{α} = \frac{A - 4}{A} \times Q$
$\Rightarrow 48 = \frac{A - 4}{A} \times 50$
$\Rightarrow A = 100$