Question

In an adsorption experiment, a graph between $\log (x/m)$ versus $\log P$ was found to be linear with a slope of $45^{\circ }.$ The intercept on the $y$ axis was found to be $\mathrm{0.301.}$ Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of $3.0$ atm.

Answer 1

Answer: 6

$\log \frac{x}{m}\equiv \log K+\frac{1}{n}\log P$

$\therefore$ Plot of log $\frac{x}{m}$ versus log $P$ is linear with slope $\equiv \frac{1}{n}$ and intercept $=\log k$

Thus $\frac{1}{n}=\tan \theta =\tan 45^{\circ }=1$ or $n=1$

$\log K=0.301$ or $K=$ antilog $0.301=2$

At $P=3atm$

$\frac{x}{m}=K{P}^{1/n}=2\times (3{)}^1=6$