Question

In an adsorption experiment, a graph between $\log (x / m)$ versus $\log\, P$ was found to be linear with a slope of $45^{\circ} .$ The intercept on the $y$ axis was found to be $0.301 .$ Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of $3.0$ atm.

Answer 1

$\log \frac{x}{m} \equiv \log \,K+\frac{1}{n} \log\, P$

$\therefore $ Plot of log $\frac{x}{m}$ versus log $P$ is linear with slope $\equiv \frac{1}{n}$ and intercept $=\log\, k$

Thus $\frac{1}{n}=\tan\, \theta=\tan \,45^{\circ}=1$ or $n=1$

$\log \,K=0.301$ or $K =$ antilog $0.301=2$

At $P=3\, atm$

$\frac{x}{m}=K P^{1 / n}=2 \times(3)^{1}=6$