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Tardigrade
Question
Physics
In an adiabatic process, the density of a diatomic gas becomes 32 times its initial value. The final pressure of the gas is found to be n times the initial pressure. The value of n is:
Q. In an adiabatic process, the density of a diatomic gas becomes
32
times its initial value. The final pressure of the gas is found to be
n
times the initial pressure. The value of
n
is:
6310
214
JEE Main
JEE Main 2020
Thermodynamics
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A
326
10%
B
32
1
41%
C
32
19%
D
128
29%
Solution:
In adiabatic proccss
P
Vγ
=
constant
P
(
ρ
m
)
γ
=
constant
as mass is constant
P
∝
ρ
γ
P
i
P
f
=
(
ρ
i
ρ
f
)
γ
=
(
32
)
7/5
=
2
7
=
128