In an ac generator, a rectangular coil of 100 turns each having area 14 × 10-2 m 2 is rotated at 360 rev / min about an axis perpendicular to a uniform magnetic field of magnitude 3.0 T. The maximum value of the emf produced will be V. (. Take .π=(22/7))

Question

In an ac generator, a rectangular coil of 100 turns each having area 14 × 10-2 m 2 is rotated at 360 rev / min about an axis perpendicular to a uniform magnetic field of magnitude 3.0 T. The maximum value of the emf produced will be V. (. Take .π=(22/7)) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

xi max = NAB ω =100 × 14 × 10-2 × 3 × (360 × 2 π/60) =1584 V

Q. In an ac generator, a rectangular coil of 100 turns each having area 14×10−2m2 is rotated at 360 rev / min about an axis perpendicular to a uniform magnetic field of magnitude 3.0T. The maximum value of the emf produced will be ________ V. ( Take π=722​)

ξmax​=NABω =100×14×10−2×3×60360×2π​ =1584V

$ξ_{m a x} = N A B ω$
$= 100 \times 14 \times 1 0^{- 2} \times 3 \times \frac{360 \times 2 π}{60}$
$= 1584 V$