In an AC circuit, a resistance of R ohm is connected in series with an inductance L. If phase angle between voltage and current is 45°, the value of inductive reactance will be

Question

In an AC circuit, a resistance of R ohm is connected in series with an inductance L. If phase angle between voltage and current is 45°, the value of inductive reactance will be (A) (R/4) (B) (R/2) (C) R (D) Cannot be found with the given data

Tardigrade Admin · Accepted Answer

tan φ=(XL/R) ⇒ tan 45°=(XL/R)=1 ⇒ XL=R

Q. In an AC circuit, a resistance of $R o hm$ is connected in series with an inductance $L$ . If phase angle between voltage and current is $4 5^{\circ}$ , the value of inductive reactance will be

$\frac{R}{4}$

$\frac{R}{2}$

R

Cannot be found with the given data

$tan ϕ = \frac{X _{L}}{R}$
$\Rightarrow tan 4 5^{\circ} = \frac{X _{L}}{R} = 1$
$\Rightarrow X_{L} = R$

Q. In an AC circuit, a resistance of Rohm is connected in series with an inductance L. If phase angle between voltage and current is 45∘, the value of inductive reactance will be

4R​

2R​

R

Cannot be found with the given data

tanϕ=RXL​​ ⇒tan45∘=RXL​​=1 ⇒XL​=R

Q. In an AC circuit, a resistance of $R o hm$ is connected in series with an inductance $L$ . If phase angle between voltage and current is $4 5^{\circ}$ , the value of inductive reactance will be

$\frac{R}{4}$

$\frac{R}{2}$

$tan ϕ = \frac{X _{L}}{R}$
$\Rightarrow tan 4 5^{\circ} = \frac{X _{L}}{R} = 1$
$\Rightarrow X_{L} = R$