In alkaline medium, KMnO4 reacts as follows 2KMnO4 + 2KOH → 2K2MnO4 + H2O+ O Therefore, the equivalent mass of KMnO4 will be

Question

In alkaline medium, KMnO4 reacts as follows 2KMnO4 + 2KOH → 2K2MnO4 + H2O+ O Therefore, the equivalent mass of KMnO4 will be (A) 31.6 (B) 52.7 (C) 7.0 (D) 158.0

Tardigrade Admin · Accepted Answer

E=(M.M/Valence factor)=(158/1) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6cc60b406bc5cdac727bceca99d1b6bd-.jpeg" />

Q. In alkaline medium, $K M n O_{4}$ reacts as follows
$2 K M n O_{4} + 2 K O H \to 2 K_{2} M n O_{4} + H_{2} O + O$
Therefore, the equivalent mass of $K M n O_{4}$ will be

$31.6$

$52.7$

$7.0$

$158.0$

$E = \frac{M . M}{Va l e n ce f a c t or} = \frac{158}{1}$

Q. In alkaline medium, KMnO4​ reacts as follows 2KMnO4​+2KOH→2K2​MnO4​+H2​O+O Therefore, the equivalent mass of KMnO4​ will be

31.6

52.7

7.0

158.0