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  4. In alkaline medium, KMnO4 reacts as follows 2KMnO4 + 2KOH → 2K2MnO4 + H2O+ O Therefore, the equivalent mass of KMnO4 will be

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Q. In alkaline medium, $KMnO_{4}$ reacts as follows
$2KMnO_{4} + 2KOH \to 2K_{2}MnO_{4} + H_{2}O+ O$
Therefore, the equivalent mass of $KMnO_{4}$ will be

Redox Reactions

Solution:

$E=\frac{M.M}{Valence factor}=\frac{158}{1}$
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