Question

In $[Ag(CN{)}_2{]}^{-}$ , the number of $\pi$ bonds is

• A. 2
• B. 3
• C. 4
• D. 6

Answer 1

Answer: (C)

In $Ag{\left[(CN{)}_2\right]}^{2-},C{N}^{-}$has $\pi$ bonds $C\equiv N$ so two $\pi$-bonds are present in one $CN$ so, the number of $\pi$ bonds are $2\times 2=4$.