In acidic medium potassium dichromate acts as an oxidant according to the equation, Cr2O+14H++6e-→2Cr3++7H2O What is the equivalent weight of K2Cr2O7? (mol. Wt. = M)

Question

In acidic medium potassium dichromate acts as an oxidant according to the equation, Cr2O+14H++6e-→2Cr3++7H2O What is the equivalent weight of K2Cr2O7? (mol. Wt. = M) (A) M (B) M/2 (C) M/3 (D) M/6

Tardigrade Admin · Accepted Answer

Since it accept 6e- its Equivalent weight =(M/6)

Q. In acidic medium potassium dichromate acts as an oxidant according to the equation,
$C r_{2} O + 14 H^{+} + 6 e^{-} \to 2 C r^{3 +} + 7 H_{2} O$ What is the equivalent weight of $K_{2} C r_{2} O_{7} ?$ (mol. Wt. = M)

$M$

$M /2$

$M /3$

$M /6$

Since it accept $6 e^{-}$ its Equivalent weight $= \frac{M}{6}$

Q. In acidic medium potassium dichromate acts as an oxidant according to the equation, Cr2​O+14H++6e−→2Cr3++7H2​O What is the equivalent weight of K2​Cr2​O7​? (mol. Wt. = M)

M

M/2

M/3

M/6

Since it accept 6e− its Equivalent weight =6M​

Q. In acidic medium potassium dichromate acts as an oxidant according to the equation,
$C r_{2} O + 14 H^{+} + 6 e^{-} \to 2 C r^{3 +} + 7 H_{2} O$ What is the equivalent weight of $K_{2} C r_{2} O_{7} ?$ (mol. Wt. = M)

$M$

$M /2$

$M /3$

$M /6$

Since it accept $6 e^{-}$ its Equivalent weight $= \frac{M}{6}$