In acidic medium MnO4 is converted to Mn2+ . The quantity of electricity in faraday required to reduce 0.5 mole of MnO4 to Mn2+ would be :

Question

In acidic medium MnO4 is converted to Mn2+ . The quantity of electricity in faraday required to reduce 0.5 mole of MnO4 to Mn2+ would be : (A)  2.5  (B)  5  (C)  1  (D)  0.5

Tardigrade Admin · Accepted Answer

In MnO4- the oxidation number of Mn is +7 ∴ overset+7Mn + 5e- → overset+7Mn In the reaction, 5 electrons are involved hence 5 faraday will be needed for the reduction of 1 mole of MnO4- Therefore for 0.5 mole of MnO4-. number of faradays required = 2.5 F

Q. In acidic medium $M n O_{4}$ is converted to $M n^{2 +}$ . The quantity of electricity in faraday required to reduce $0.5$ mole of $M n O_{4}$ to $M n^{2 +}$ would be :

$2.5$

$5$

$1$

$0.5$

Q. In acidic medium MnO4​ is converted to Mn2+ . The quantity of electricity in faraday required to reduce 0.5 mole of MnO4​ to Mn2+ would be :

2.5

5

1

0.5

In MnO4−​ the oxidation number of Mn is +7 ∴Mn+7+5e−→Mn+7 In the reaction, 5 electrons are involved hence 5 faraday will be needed for the reduction of 1 mole of MnO4−​ Therefore for 0.5 mole of MnO4−​. number of faradays required =2.5F

Q. In acidic medium $M n O_{4}$ is converted to $M n^{2 +}$ . The quantity of electricity in faraday required to reduce $0.5$ mole of $M n O_{4}$ to $M n^{2 +}$ would be :

$2.5$

$5$

$1$

$0.5$