Question

In accordance with the Bohr's model, the quantum number that characterises the Earth's revolution around the sun in an orbit of radius $1.5\times 10^{11}m$ with orbital speed $3\times 10^{4}m{s}^{-1}$ is
[given mass of Earth $=6\times 10^{24}kg$ ]

• A. $8.57\times 10^{64}$
• B. $2.57\times 10^{74}$
• C. $5.98\times 10^{86}$
• D. $2.57\times 10^{38}$

Answer 1

Answer: (B)

$m{v}_{0}r=n\frac{h}{2\pi }$