In a Young's double slit experiment, the slit separation is 1 mm and the screen is 1 m from the slit. For a monochromatic light of wavelength 500 nm , the distance of 3 textrd minima from the central maxima is

Question

In a Young's double slit experiment, the slit separation is 1 mm and the screen is 1 m from the slit. For a monochromatic light of wavelength 500 nm , the distance of 3 textrd minima from the central maxima is (A)  0.50 mm  (B)  1.25 mm  (C)  1.50 mm  (D)  1.75 mm

Tardigrade Admin · Accepted Answer

Given, d=1 mm =1 × 10-3 m , D=1 m λ=500 nm =500 × 10-9 m Distance of nth minima from central maxima maximax xn=((2 n-1) λ/2) (D/d) =((2 × 3-1) × 500 × 10-9/2) × (1/1 × 10-3) =2.5 × 500 × 10-6 =12.5 × 10-4 m =1.25 nm

Q. In a Young's double slit experiment, the slit separation is $1 mm$ and the screen is $1 m$ from the slit. For a monochromatic light of wavelength $500 nm$ , the distance of $3^{rd}$ minima from the central maxima is

$0.50 mm$

$1.25 mm$

$1.50 mm$

$1.75 mm$

Q. In a Young's double slit experiment, the slit separation is 1mm and the screen is 1m from the slit. For a monochromatic light of wavelength 500nm , the distance of 3rd minima from the central maxima is

0.50mm

1.25mm

1.50mm

1.75mm

Given, d=1mm=1×10−3m,D=1m λ=500nm=500×10−9m Distance of nth minima from central maxima maximax xn​=2(2n−1)λ​dD​ =2(2×3−1)×500×10−9​×1×10−31​ =2.5×500×10−6 =12.5×10−4m =1.25nm

Q. In a Young's double slit experiment, the slit separation is $1 mm$ and the screen is $1 m$ from the slit. For a monochromatic light of wavelength $500 nm$ , the distance of $3^{rd}$ minima from the central maxima is

$0.50 mm$

$1.25 mm$

$1.50 mm$

$1.75 mm$