In a Young’s double slit experiment, the separation of the two slits is doubled. To keep the same spacing of fringes, the distance D of the screen from the slits should be made

Question

In a Young’s double slit experiment, the separation of the two slits is doubled. To keep the same spacing of fringes, the distance D of the screen from the slits should be made (A)  (D/2)  (B)  (D/√ 2)  (C)  2D  (D)  4 D

Tardigrade Admin · Accepted Answer

If new value of distance of screen from double slit be D', then β'=(λ D'/d')=(λ D'/(2 d))=(λ D/d)=β ⇒ D'=2D

Q. In a Young’s double slit experiment, the separation of the two slits is doubled. To keep the same spacing of fringes, the distance $D$ of the screen from the slits should be made

$\frac{D}{2}$

$\frac{D}{2}$

$2 D$

$4 D$

If new value of distance of screen from double slit be $D^{'}$ , then
$β^{'} = \frac{λ D ^{'}}{d ^{'}} = \frac{λ D ^{'}}{( 2 d )} = \frac{λ D}{d} = β$
$\Rightarrow D^{'} = 2 D$

Q. In a Young’s double slit experiment, the separation of the two slits is doubled. To keep the same spacing of fringes, the distance D of the screen from the slits should be made

2D​

2​D​

2D

4D

If new value of distance of screen from double slit be D′, then β′=d′λD′​=(2d)λD′​=dλD​=β ⇒D′=2D

Q. In a Young’s double slit experiment, the separation of the two slits is doubled. To keep the same spacing of fringes, the distance $D$ of the screen from the slits should be made

$\frac{D}{2}$

$\frac{D}{2}$

$2 D$

$4 D$

If new value of distance of screen from double slit be $D^{'}$ , then
$β^{'} = \frac{λ D ^{'}}{d ^{'}} = \frac{λ D ^{'}}{( 2 d )} = \frac{λ D}{d} = β$
$\Rightarrow D^{'} = 2 D$