Thank you for reporting, we will resolve it shortly
Q.
In a Young’s double slit experiment, the separation of the two slits is doubled. To keep the same spacing of fringes, the distance $ D $ of the
screen from the slits should be made
If new value of distance of screen from double slit be $D'$, then
$\beta'=\frac{\lambda D'}{d'}=\frac{\lambda D'}{(2 d)}=\frac{\lambda D}{d}=\beta$
$\Rightarrow D'=2D$