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Q. In a Young’s double slit experiment, the separation of the two slits is doubled. To keep the same spacing of fringes, the distance $ D $ of the screen from the slits should be made

UPSEEUPSEE 2010Wave Optics

Solution:

If new value of distance of screen from double slit be $D'$, then
$\beta'=\frac{\lambda D'}{d'}=\frac{\lambda D'}{(2 d)}=\frac{\lambda D}{d}=\beta$
$\Rightarrow D'=2D$