In a Young’s double slit experiment, the fringe width is found to be 2 mm , when light of wavelength 6000 mathringA is used. Find the change in fringe width if the whole apparatus is immersed in water of refractive index 1.33 .

Question

In a Young’s double slit experiment, the fringe width is found to be 2 mm , when light of wavelength 6000 mathringA is used. Find the change in fringe width if the whole apparatus is immersed in water of refractive index 1.33 . (A)  0.5 mm  (B)  1 mm  (C)  1.5 mm  (D)  2 mm

Tardigrade Admin · Accepted Answer

Fringe width β =2 mm =2 × 10-3 m λ =6000 mathringA μ =1.33 β' =? β'=(β/μ) =(2/1.33)=1.5 mm

Q. In a Young’s double slit experiment, the fringe width is found to be $2 mm$ , when light of wavelength $6000 \overset{˚}{A}$ is used. Find the change in fringe width if the whole apparatus is immersed in water of refractive index $1.33$ .

$0.5 mm$

$1 mm$

$1.5 mm$

$2 mm$

Fringe width $β = 2 mm = 2 \times 1 0^{- 3} m$
$λ = 6000 \overset{˚}{A}$
$μ = 1.33$
$β^{'} = ?$
$β^{'} = \frac{β}{μ}$
$= \frac{2}{1.33} = 1.5 mm$

Q. In a Young’s double slit experiment, the fringe width is found to be 2mm , when light of wavelength 6000A˚ is used. Find the change in fringe width if the whole apparatus is immersed in water of refractive index 1.33 .

0.5mm

1mm

1.5mm

2mm