In a Young's double slit experiment, the angular width of a fringe formed on a distant screen is 1°. The slit separation is 0.01 mm. The wavelength of the light is

Question

In a Young's double slit experiment, the angular width of a fringe formed on a distant screen is 1°. The slit separation is 0.01 mm. The wavelength of the light is (A) 0.174 nm (B) 0.174 mathringA (C) 0.174 μ m (D) 0.174 × 10-4 m

Tardigrade Admin · Accepted Answer

Angular fringe width, θ = (λ/d) ∴ λ = θ d Here, d = 0.01 mm = 10-5 m, θ = 1° = (π/180) radians λ = (π/180)×10-5 = 1.74 ×10-7 m = 0.174 ×10-6 m = 0.174 μ m

Q. In a Young's double slit experiment, the angular width of a fringe formed on a distant screen is $1^{\circ}$ . The slit separation is $0.01 mm$ . The wavelength of the light is

$0.174 nm$

$0.174 \overset{˚}{A}$

$0.174 μ m$

$0.174 \times 1 0^{- 4} m$

Angular fringe width,
$θ = \frac{λ}{d}$
$∴ λ = θ d$
Here, $d = 0.01 mm$
$= 1 0^{- 5} m, θ = 1^{\circ}$
$= \frac{π}{180}$ radians
$λ = \frac{π}{180} \times 1 0^{- 5}$
$= 1.74 \times 1 0^{- 7} m$
$= 0.174 \times 1 0^{- 6} m$
$= 0.174 μ m$

Q. In a Young's double slit experiment, the angular width of a fringe formed on a distant screen is 1∘. The slit separation is 0.01mm. The wavelength of the light is

0.174nm

0.174A˚

0.174μm

0.174×10−4m