In a Young's double slit experiment, light of 500 nm is used to produce an interference pattern. When the distance between the slits is 0.05 mm , the angular width (in degree) of the fringes formed on the distance screen is close to:

Question

In a Young's double slit experiment, light of 500 nm is used to produce an interference pattern. When the distance between the slits is 0.05 mm , the angular width (in degree) of the fringes formed on the distance screen is close to: (A) 0.07° (B) 0.17° (C) 1.7° (D) 0.57°

Tardigrade Admin · Accepted Answer

Δ θ0=((λ/ d ) × (180/π))0 =0.57°

Q. In a Young's double slit experiment, light of $500 nm$ is used to produce an interference pattern. When the distance between the slits is $0.05 mm,$ the angular width (in degree) of the fringes formed on the distance screen is close to:

$0.0 7^{\circ}$

$0.1 7^{\circ}$

$1. 7^{\circ}$

$0.5 7^{\circ}$

$Δ θ_{0} = (\frac{λ}{d} \times \frac{180}{π})^{0}$
$= 0.5 7^{\circ}$

Q. In a Young's double slit experiment, light of 500nm is used to produce an interference pattern. When the distance between the slits is 0.05mm, the angular width (in degree) of the fringes formed on the distance screen is close to:

0.07∘

0.17∘

1.7∘

0.57∘