In a vernier callipers, N divisions of vernier scale coincide with (N - 1) division of main scale (in which one division represents 1 mm). The vernier constant is (cm)

Question

In a vernier callipers, N divisions of vernier scale coincide with (N - 1) division of main scale (in which one division represents 1 mm). The vernier constant is (cm) (A) N (B) N - 1 (C)  (1/N-1)  (D)  (1/10 N)

Tardigrade Admin · Accepted Answer

N VSD = (N - 1) MSD 1 VSD = (N-1/N) = MSD V.C. = 1 MSD - 1 VSD = 1 MSD - ((N-1/N)) MSD = (1/N) MSD = (1/N) mm = (1/10 N) cm

Q. In a vernier callipers, N divisions of vernier scale coincide with (N - 1) division of main scale (in which one division represents 1 mm). The vernier constant is (cm)

$N$

$N - 1$

$\frac{1}{N - 1}$

$\frac{1}{10 N}$

$N V S D = (N - 1) MS D$
$1 V S D = \frac{N - 1}{N} = MS D$
$V . C . = 1 MS D - 1 V S D$
$= 1 MS D - (\frac{N - 1}{N}) MS D = \frac{1}{N} MS D$
$= \frac{1}{N} mm = \frac{1}{10 N} c m$

Q. In a vernier callipers, N divisions of vernier scale coincide with (N - 1) division of main scale (in which one division represents 1 mm). The vernier constant is (cm)

N

N−1

N−11​

10N1​

NVSD=(N−1)MSD 1VSD=NN−1​=MSD V.C.=1MSD−1VSD =1MSD−(NN−1​)MSD=N1​MSD =N1​mm=10N1​cm

$N$

$N - 1$

$\frac{1}{N - 1}$

$\frac{1}{10 N}$

$N V S D = (N - 1) MS D$
$1 V S D = \frac{N - 1}{N} = MS D$
$V . C . = 1 MS D - 1 V S D$
$= 1 MS D - (\frac{N - 1}{N}) MS D = \frac{1}{N} MS D$
$= \frac{1}{N} mm = \frac{1}{10 N} c m$