Question

In a $△ABC$, if $b=2,\angle B=30^{\circ }$, then the area of the circumcircle of $△ABC$ (in sq units) is

• A. $\pi$
• B. $2\pi$
• C. $4\pi$
• D. $6\pi$

Answer 1

Answer: (C)

since, $R=\frac{b}{2\sin B}=\frac{2}{2\sin 30^{\circ }}=\frac{2}{1}$
$\therefore$ Area of circumcircle $=\pi R^2=\pi (2{)}^2=4\pi$ sq units