In a transformer the number of primary turns is four times that of the secondary turns. Its primary is connected to an AC source of voltage V. Then,

Question

In a transformer the number of primary turns is four times that of the secondary turns. Its primary is connected to an AC source of voltage V. Then, (A) Current through its secondary is about four times that of the current through its primary (B) Voltage across its secondary is about four times that of the voltage across its primary (C) Voltage across its secondary is about two times that of the voltage across its primary (D) Voltage across its secondary is about times that of the voltage across its primary

Tardigrade Admin · Accepted Answer

For a transformer, ratio of voltages in primary and secondary can be written as (V1/V2)=(N1/N2)=(I2/I1) ⇒ (I2/I1)=(4 N2/N2)=4 ⇒ I2=4 I1

Q. In a transformer the number of primary turns is four times that of the secondary turns. Its primary is connected to an $A C$ source of voltage $V$ . Then,

Current through its secondary is about four times that of the current through its primary

Voltage across its secondary is about four times that of the voltage across its primary

Voltage across its secondary is about two times that of the voltage across its primary

Voltage across its secondary is about times that of the voltage across its primary

For a transformer, ratio of voltages in primary and secondary can be written as
$\frac{V _{1}}{V _{2}} = \frac{N _{1}}{N _{2}} = \frac{I _{2}}{I _{1}}$
$\Rightarrow \frac{I _{2}}{I _{1}} = \frac{4 N _{2}}{N _{2}} = 4$
$\Rightarrow I_{2} = 4 I_{1}$

Q. In a transformer the number of primary turns is four times that of the secondary turns. Its primary is connected to an AC source of voltage V. Then,