In a toroid the number of turns per unit length is 1000 and current through it is (1/4 π) ampere. The magnetic field produced inside (in weber/m 2 ) will be

Question

In a toroid the number of turns per unit length is 1000 and current through it is (1/4 π) ampere. The magnetic field produced inside (in weber/m 2 ) will be (A) 10-2 (B) 10-3 (C) 10-4 (D) 10-7

Tardigrade Admin · Accepted Answer

n=1000 l=(1/4 π) A B=μ0 n i=4 π × 10-7(1000) × (1/4 π) B=10-4( T )

Q. In a toroid the number of turns per unit length is $1000$ and current through it is $\frac{1}{4 π}$ ampere. The magnetic field produced inside (in weber/m $^{2}$ ) will be

$1 0^{- 2}$

$1 0^{- 3}$

$1 0^{- 4}$

$1 0^{- 7}$

$n = 1000$
$l = \frac{1}{4 π} A$
$B = μ_{0} ni = 4 π \times 1 0^{- 7} (1000) \times \frac{1}{4 π}$
$B = 1 0^{- 4} (T)$

Q. In a toroid the number of turns per unit length is 1000 and current through it is 4π1​ ampere. The magnetic field produced inside (in weber/m 2 ) will be

10−2

10−3

10−4

10−7