In a thermodynamic process, 200J of heat is given to a gas and 100J of work is also done on it. The change in internal energy of the gas is

Question

In a thermodynamic process, 200J of heat is given to a gas and 100J of work is also done on it. The change in internal energy of the gas is (A) 100J (B) 300J (C) 419J (D) 24J

Tardigrade Admin · Accepted Answer

Δ Q=Δ U+Δ W Given, Δ Q=200J and Δ W=-100J ⇒ Δ U=Δ Q-Δ W ⇒ Δ U=200-(- 100)=300J

Q. In a thermodynamic process, $200 J$ of heat is given to a gas and $100 J$ of work is also done on it. The change in internal energy of the gas is

$100 J$

$300 J$

$419 J$

$24 J$

$Δ Q = Δ U + Δ W$
Given, $Δ Q = 200 J$ and $Δ W = - 100 J$
$\Rightarrow Δ U = Δ Q - Δ W$
$\Rightarrow Δ U = 200 - (- 100) = 300 J$

Q. In a thermodynamic process, 200J of heat is given to a gas and 100J of work is also done on it. The change in internal energy of the gas is

100J

300J

419J

24J