In a solvent 50 % of an acid HA dimerizes and the rest dissociates. The van't Hoff factor of the acid is × 10-2.

Question

In a solvent 50 % of an acid HA dimerizes and the rest dissociates. The van't Hoff factor of the acid is × 10-2. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/171292fbb6b08d940c5216b681ba56eb-.png" /> Now, i=( text final moles / text initial moles )=(0.25 a+0.5 a+0.5 a/0.5 a+0.5 a) =1.25=125 × 10-2

Q. In a solvent $50%$ of an acid HA dimerizes and the rest dissociates. The van't Hoff factor of the acid is ___ $\times 1 0^{- 2}$ .

Now, $i = \frac{final moles}{initial moles} = \frac{0.25 a + 0.5 a + 0.5 a}{0.5 a + 0.5 a}$
$= 1.25 = 125 \times 1 0^{- 2}$

Q. In a solvent 50% of an acid HA dimerizes and the rest dissociates. The van't Hoff factor of the acid is ___×10−2.

Now, i= initial moles final moles ​=0.5a+0.5a0.25a+0.5a+0.5a​ =1.25=125×10−2

Q. In a solvent $50%$ of an acid HA dimerizes and the rest dissociates. The van't Hoff factor of the acid is ___ $\times 1 0^{- 2}$ .

Now, $i = \frac{final moles}{initial moles} = \frac{0.25 a + 0.5 a + 0.5 a}{0.5 a + 0.5 a}$
$= 1.25 = 125 \times 1 0^{- 2}$