In a solid AB . A atoms are in ccp arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is Ax By. The value of x is . [nearest integer]

Question

In a solid AB . A atoms are in ccp arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is Ax By. The value of x is . [nearest integer] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

A arrow 4-(2 × (1/2))=3 B arrow 12 × (1/4)+1 × 1=4 So, Compound is A 3 B 4 The value of x is 3 .

Q. In a solid $A B . A$ atoms are in $cc p$ arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is $A_{x} B_{y}$ . The value of $x$ is ____. [nearest integer]

$A \to 4 - (2 \times \frac{1}{2}) = 3$
$B \to 12 \times \frac{1}{4} + 1 \times 1 = 4$
So, Compound is $A_{3} B_{4}$
The value of $x$ is $3$ .

Q. In a solid AB.A atoms are in ccp arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is Ax​By​. The value of x is ____. [nearest integer]

A→4−(2×21​)=3 B→12×41​+1×1=4 So, Compound is A3​B4​ The value of x is 3 .

Q. In a solid $A B . A$ atoms are in $cc p$ arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is $A_{x} B_{y}$ . The value of $x$ is ____. [nearest integer]

$A \to 4 - (2 \times \frac{1}{2}) = 3$
$B \to 12 \times \frac{1}{4} + 1 \times 1 = 4$
So, Compound is $A_{3} B_{4}$
The value of $x$ is $3$ .