In a single slit diffraction, slit width is 0.6 mm and distance of first minima from central position is 1 mm. If screen distance is 1.2 m, then wavelength of light (in nm ) is

Question

In a single slit diffraction, slit width is 0.6 mm and distance of first minima from central position is 1 mm. If screen distance is 1.2 m, then wavelength of light (in nm ) is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(λ D/a) =y ⇒ λ=(a y/D) =(0.6 × 10-3 × 10-3/1.2) =0.5 × 10-6 m =500 nm

Q. In a single slit diffraction, slit width is $0.6 mm$ and distance of first minima from central position is $1 mm$ . If screen distance is $1.2 m$ , then wavelength of light (in $nm$ ) is

$\frac{λ D}{a} = y$
$\Rightarrow λ = \frac{a y}{D}$
$= \frac{0.6 \times 1 0 ^{- 3} \times 1 0 ^{- 3}}{1.2}$
$= 0.5 \times 1 0^{- 6} m = 500 nm$

Q. In a single slit diffraction, slit width is 0.6mm and distance of first minima from central position is 1mm. If screen distance is 1.2m, then wavelength of light (in nm ) is

aλD​=y ⇒λ=Day​ =1.20.6×10−3×10−3​ =0.5×10−6m=500nm

Q. In a single slit diffraction, slit width is $0.6 mm$ and distance of first minima from central position is $1 mm$ . If screen distance is $1.2 m$ , then wavelength of light (in $nm$ ) is

$\frac{λ D}{a} = y$
$\Rightarrow λ = \frac{a y}{D}$
$= \frac{0.6 \times 1 0 ^{- 3} \times 1 0 ^{- 3}}{1.2}$
$= 0.5 \times 1 0^{- 6} m = 500 nm$