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  4. In a single slit diffraction, slit width is 0.6 mm and distance of first minima from central position is 1 mm. If screen distance is 1.2 m, then wavelength of light (in nm ) is

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Q. In a single slit diffraction, slit width is $0.6\, mm$ and distance of first minima from central position is $1\, mm$. If screen distance is $1.2\, m$, then wavelength of light (in $nm$ ) is

Wave Optics

Solution:

$\frac{\lambda D}{a} =y $
$\Rightarrow \lambda=\frac{a y}{D}$
$=\frac{0.6 \times 10^{-3} \times 10^{-3}}{1.2}$
$=0.5 \times 10^{-6} m =500\, nm$