In a single slit diffraction experiment first minimum of red light (660 nm) coincides with first maximum of some other wavelength (.in nm.) λ . Calculate λ .

Question

In a single slit diffraction experiment first minimum of red light (660 nm) coincides with first maximum of some other wavelength (.in nm.) λ . Calculate λ . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Secondary minimum sin θ =(nλ /a) sin θ =(nλ r/d) n=1 sin θ =((λ )r/a) ldots ldots (.i.) Secondary maximum sin θ =((. 2 n + 1 .) λ /2 a) n=1 sin θ =(3 λ /2 d) ldots ldots (.ii.) (i)=(ii) (λ r/d)=(3 λ /2 d) λ =(2 λ r/3) =(2 × 660 × 10- 9/3) λ =440 nm

Q. In a single slit diffraction experiment first minimum of red light (660nm) coincides with first maximum of some other wavelength (innm) λ . Calculate λ .

Secondary minimum sinθ=anλ​ sinθ=dnλr​​ n=1 sinθ=a(λ)r​​……(i) Secondary maximum sinθ=2a(2n+1)λ​ n=1 sinθ=2d3λ​……(ii) (i)=(ii) dλr​​=2d3λ​ λ=32λr​​ =32×660×10−9​ λ=440nm

Q. In a single slit diffraction experiment first minimum of red light $(660 nm)$ coincides with first maximum of some other wavelength $(in nm)$ $λ$ . Calculate $λ$ .