In a series LCR circuit, the voltage across resistance, capacitance and inductance is 10 V each. If the capacitor is removed, the voltage across the inductance will be

Question

In a series LCR circuit, the voltage across resistance, capacitance and inductance is 10 V each. If the capacitor is removed, the voltage across the inductance will be (A) 10 V (B) 10√2 V (C) (10/√2)V (D) 20 V

Tardigrade Admin · Accepted Answer

Given, VR=VL=VC=10V This means the LCR circuit is in resonance and the reactance of inductor and capacitor is equal to the resistance of the resistor. ⇒ Vs u p p l y=VR=10 V After removing capacitor Vs u p p l y=√VR2 + VL2 Since, VR=VL ⇒ 10=√VL2 + VL2 ⇒ 2VL2=100 VL=(10/√2) V

Q. In a series $L CR$ circuit, the voltage across resistance, capacitance and inductance is $10 V$ each. If the capacitor is removed, the voltage across the inductance will be

$10 V$

$102 V$

$\frac{10}{2} V$

$20 V$

Q. In a series LCR circuit, the voltage across resistance, capacitance and inductance is 10V each. If the capacitor is removed, the voltage across the inductance will be

10V

102​V

2​10​V

20V

Q. In a series $L CR$ circuit, the voltage across resistance, capacitance and inductance is $10 V$ each. If the capacitor is removed, the voltage across the inductance will be

$10 V$

$102 V$

$\frac{10}{2} V$

$20 V$