In a series LCR circuit R =200Ω and the voltage and the frequency of the main supply is 220 V and 50 Hz respectively. On taking but the capacitance from the circuit the current lags behind the voltage by 30°. On taking out the inductor from the circuit the current leads the voltage by 30°. The power dissipated in the LCR circuit is

Question

In a series LCR circuit R =200Ω and the voltage and the frequency of the main supply is 220 V and 50 Hz respectively. On taking but the capacitance from the circuit the current lags behind the voltage by 30°. On taking out the inductor from the circuit the current leads the voltage by 30°. The power dissipated in the LCR circuit is (A) 305 W (B) 210 W (C) zero (D) 242 W

Tardigrade Admin · Accepted Answer

The given, circuit is under resonance as XL=Xc Hence pmower dissipated in the circuit is P=(V2/R)=242 W

$305 W$

$210 W$

zero

$242 W$

The given, circuit is under resonance as
$X_{L} = X_{c}$
Hence pmower dissipated in the circuit is
$P = \frac{V ^{2}}{R} = 242 W$

305W

210W

zero

242W

The given, circuit is under resonance as XL​=Xc​ Hence pmower dissipated in the circuit is P=RV2​=242W

$305 W$

$210 W$

$242 W$

The given, circuit is under resonance as
$X_{L} = X_{c}$
Hence pmower dissipated in the circuit is
$P = \frac{V ^{2}}{R} = 242 W$