In a saturated solution of calcium phosphate, the concentration of PO 4-3 ions is 3.3 × 10-7. The Ks p of Ca 3( PO 4)2 will be

Question

In a saturated solution of calcium phosphate, the concentration of PO 4-3 ions is 3.3 × 10-7. The Ks p of Ca 3( PO 4)2 will be (A) 1.32 × 10-31 (B) 1.32 × 10-32 (C) 1.32 × 10-33 (D) 1.32 × 10-33.

Tardigrade Admin · Accepted Answer

[ PO 4-3]=3.3 × 10-7 M [ Ca 2+]=(3/2) ×[ PO 4-3]=(3/2) × 3.3 × 10-7=5 × 10-7 M Ks p Ca 3( PO 4)2=[ Ca 2+]3[ PO 4-3]2 ⇒(5 × 10-7)3(3.3 × 10-7)2=1.32 × 10-32

Q. In a saturated solution of calcium phosphate, the concentration of $P O_{4}^{- 3}$ ions is $3.3 \times 1 0^{- 7}$ . The $K_{s p}$ of $C a_{3} (P O_{4})_{2}$ will be

$1.32 \times 1 0^{- 31}$

$1.32 \times 1 0^{- 32}$

$1.32 \times 1 0^{- 33}$

$1.32 \times 1 0^{- 33}$ .

Q. In a saturated solution of calcium phosphate, the concentration of PO4−3​ ions is 3.3×10−7. The Ksp​ of Ca3​(PO4​)2​ will be

1.32×10−31

1.32×10−32

1.32×10−33

1.32×10−33.

[PO4−3​]=3.3×10−7M [Ca2+]=23​×[PO4−3​]=23​×3.3×10−7=5×10−7M Ksp​Ca3​(PO4​)2​=[Ca2+]3[PO4−3​]2 ⇒(5×10−7)3(3.3×10−7)2=1.32×10−32

Q. In a saturated solution of calcium phosphate, the concentration of $P O_{4}^{- 3}$ ions is $3.3 \times 1 0^{- 7}$ . The $K_{s p}$ of $C a_{3} (P O_{4})_{2}$ will be

$1.32 \times 1 0^{- 31}$

$1.32 \times 1 0^{- 32}$

$1.32 \times 1 0^{- 33}$

$1.32 \times 1 0^{- 33}$ .