In a right angled triangle, the length of the sides are a and b (0

Question

In a right angled triangle, the length of the sides are a and b (0< a < b ). A circle passes through the mid-point of the smaller side and touches the hypotenuse at its mid-point. (A) centre of the circle is ((2 a2-b2/4 a), (b/4)) (B) centre of the circle is ((2 b 2- a 2/4 b ), ( b /4)) (C) radius of the circle is (b √a2+b2/4 a) (D) radius of the circle is (a √a2+b2/4 b)

Tardigrade Admin · Accepted Answer

Correct answer is (a) centre of the circle is ((2 a2-b2/4 a), (b/4))Correct answer is (c) radius of the circle is (b √a2+b2/4 a)

Q. In a right angled triangle, the length of the sides are $a$ and $b (0 < a < b)$ . A circle passes through the mid-point of the smaller side and touches the hypotenuse at its mid-point.

centre of the circle is $(\frac{2 a ^{2} - b ^{2}}{4 a}, \frac{b}{4})$

centre of the circle is $(\frac{2 b ^{2} - a ^{2}}{4 b}, \frac{b}{4})$

radius of the circle is $\frac{b a ^{2} + b ^{2}}{4 a}$

radius of the circle is $\frac{a a ^{2} + b ^{2}}{4 b}$

Correct answer is (a) centre of the circle is $(\frac{2 a ^{2} - b ^{2}}{4 a}, \frac{b}{4})$ Correct answer is (c) radius of the circle is $\frac{b a ^{2} + b ^{2}}{4 a}$

Q. In a right angled triangle, the length of the sides are a and b(0<a<b). A circle passes through the mid-point of the smaller side and touches the hypotenuse at its mid-point.

centre of the circle is (4a2a2−b2​,4b​)

centre of the circle is (4b2b2−a2​,4b​)

radius of the circle is 4aba2+b2​​

radius of the circle is 4baa2+b2​​