In a resonance tube, using a tuning fork of frequency 325 Hz , two successive resonance length are observed as 25.4 cm and 77.4 cm respectively. The velocity of sound in air is

Question

In a resonance tube, using a tuning fork of frequency 325 Hz , two successive resonance length are observed as 25.4 cm and 77.4 cm respectively. The velocity of sound in air is (A) 338 m s- 1 (B) 328 m s- 1 (C) 330 m s- 1 (D) 320 m s- 1

Tardigrade Admin · Accepted Answer

v=2n(l2 - l1)=2× 325(77.4 - 25.4 )cm s- 1 =(650 × 52/100) m s- 1=338 m s- 1

Q. In a resonance tube, using a tuning fork of frequency $325 Hz$ , two successive resonance length are observed as $25.4 c m$ and $77.4 c m$ respectively. The velocity of sound in air is

$338 m s^{- 1}$

$328 m s^{- 1}$

$330 m s^{- 1}$

$320 m s^{- 1}$

$v = 2 n (l_{2} - l_{1}) = 2 \times 325 (77.4 - 25.4) c m s^{- 1}$

$= \frac{650 \times 52}{100} m s^{- 1} = 338 m s^{- 1}$

Q. In a resonance tube, using a tuning fork of frequency 325Hz , two successive resonance length are observed as 25.4cm and 77.4cm respectively. The velocity of sound in air is

338ms−1

328ms−1

330ms−1

320ms−1