In a regular octahedral molecule, MX6 the number of X-M-X bonds at 180° is

Question

In a regular octahedral molecule, MX6 the number of X-M-X bonds at 180° is (A) three (B) two (C) six (D) four

Tardigrade Admin · Accepted Answer

In octahedral structure MX6, the six hybrid orbitals (sp3d2) are directed towards the corners of a regular octahedral with an angle of 90° . According to following structure of MX6, the number of X-M-X bonds at 180° must be three.

Q. In a regular octahedral molecule, $M X_{6}$ the number of $X - M - X$ bonds at $180^{\circ}$ is

three

two

six

four

In octahedral structure $M X_{6},$ the six hybrid orbitals $(s p^{3} d^{2})$ are directed towards the corners of a regular octahedral with an angle of $90^{\circ}$ . According to following structure of $M X_{6},$ the number of $X - M - X$ bonds at $18 0^{\circ}$ must be three.

Q. In a regular octahedral molecule, MX6​ the number of X−M−X bonds at 180∘ is

three

two

six

four

In octahedral structure MX6​, the six hybrid orbitals (sp3d2) are directed towards the corners of a regular octahedral with an angle of 90∘ . According to following structure of MX6​, the number of X−M−X bonds at 180∘ must be three.

Q. In a regular octahedral molecule, $M X_{6}$ the number of $X - M - X$ bonds at $180^{\circ}$ is

In octahedral structure $M X_{6},$ the six hybrid orbitals $(s p^{3} d^{2})$ are directed towards the corners of a regular octahedral with an angle of $90^{\circ}$ . According to following structure of $M X_{6},$ the number of $X - M - X$ bonds at $18 0^{\circ}$ must be three.