In a region, the intensity of an electric field is given by E =2 i +3 j + k in NC -1 . The electric flux through a surface S =10 i m 2 in the region is

Question

In a region, the intensity of an electric field is given by E =2 i +3 j + k in NC -1 . The electric flux through a surface S =10 i m 2 in the region is (A) 5 Nm2C-1 (B) 10 Nm2C-1 (C) 15 Nm2 C-1 (D)  20 Nm2 C-1

Tardigrade Admin · Accepted Answer

Given E =(2 i +3 j + k ) NC -1 and S =10 i m 2 We know that φ = E ⋅ S φ =(2 i +3 j + k ) ⋅(10 i ) φ =20 Nm 2 C -1

Q. In a region, the intensity of an electric field is given by $E = 2 i + 3 j + k$ in $N C^{- 1} .$ The electric flux through a surface $S = 10 i m^{2}$ in the region is

$5 N m^{2} C^{- 1}$

$10 N m^{2} C^{- 1}$

$15 N m^{2} C^{- 1}$

$20 N m^{2} C^{- 1}$

Given $E = (2 i + 3 j + k) N C^{- 1}$
and $S = 10 i m^{2}$
We know that
$ϕ = E \cdot S$
$ϕ = (2 i + 3 j + k) \cdot (10 i)$
$ϕ = 20 N m^{2} C^{- 1}$

Q. In a region, the intensity of an electric field is given by E=2i+3j+k in NC−1. The electric flux through a surface S=10im2 in the region is

5Nm2C−1

10Nm2C−1

15Nm2C−1

20Nm2C−1