Question

In a reaction the ferroụs $\left(F{e}^{++}\right)$ iron is oxidized to ferric $\left(F{e}^{+++}\right)$ ion. The equivalent weight of the ion in the above reaction is equal to

• A. The atomic weight
• B. 1 / 5 of the atomic weight
• C. Half of the atomic weight
• D. Twice the atomic weight

Answer 1

Answer: (A)

The atomic weight:

Equivalent weight $=\frac{\text{ Atomic weight }}{\text{ No. of }{e}^{-}\text{lost or gained }}$

$F{e}^{2+}\to F{e}^{3+}+e^{-}$

$\therefore$ Equivalent weight $=$ Atomic weight