Question

In a reaction the ferroụs $\left( Fe ^{++}\right)$ iron is oxidized to ferric $\left( Fe ^{+++}\right)$ ion. The equivalent weight of the ion in the above reaction is equal to

• A. The atomic weight
• B. 1 / 5 of the atomic weight
• C. Half of the atomic weight
• D. Twice the atomic weight

Answer 1

Answer: (A)

The atomic weight:

Equivalent weight $=\frac{\text { Atomic weight }}{\text { No. of } e^{-} \text {lost or gained }}$

$Fe ^{2+} \rightarrow Fe ^{3+}+e^{-}$

$\therefore $ Equivalent weight $=$ Atomic weight