In a reaction the concentration of a reactant [A] changes from 0.200 mol L-1 to 50 mol L-1 in 10 min. The average rate of reaction during this interval is

Question

In a reaction the concentration of a reactant [A] changes from 0.200 mol L-1 to 50 mol L-1 in 10 min. The average rate of reaction during this interval is (A) 0.5 mol L-1 min -1  (B) 0.005 mol L-1 min -1  (C) 0.35 mol L-1 min -1  (D) 0.850 mol L-1 min -1

Tardigrade Admin · Accepted Answer

Δ [A]=[A]final-[A]initial=[0.150-0.200] =- 0.050 mol L-1 Average rate of reaction =-(Δ A/dt)=-(- [0.050]/10) =0.0050 mol L-1 min -1.

Q. In a reaction the concentration of a reactant [A] changes from 0.200 mol $L^{- 1}$ to 50 mol $L^{- 1}$ in 10 min. The average rate of reaction during this interval is

0.5 mol $L^{- 1} min^{- 1}$

0.005 mol $L^{- 1} min^{- 1}$

0.35 mol $L^{- 1} min^{- 1}$

0.850 mol $L^{- 1} min^{- 1}$

$Δ [A] = [A]_{f ina l} - [A]_{ini t ia l} = [0.150 - 0.200]$ $= - 0.050 m o l L^{- 1}$ Average rate of reaction $= - \frac{Δ A}{d t} = - \frac{- [ 0.050 ]}{10}$ $= 0.0050 m o l L^{- 1} min^{- 1} .$

Q. In a reaction the concentration of a reactant [A] changes from 0.200 mol L−1 to 50 mol L−1 in 10 min. The average rate of reaction during this interval is

0.5 mol L−1min−1

0.005 mol L−1min−1

0.35 mol L−1min−1

0.850 mol L−1min−1