In a pseudo first order hydrolysis of ester in water, the following results were obtained. t/s 0 30 60 90 Ester/mol L-1 0.55 0.31 0.17 0.085 What will be the average rate of reaction between the time interval 30 to 60 seconds?

Question

In a pseudo first order hydrolysis of ester in water, the following results were obtained. t/s 0 30 60 90 Ester/mol L-1 0.55 0.31 0.17 0.085 What will be the average rate of reaction between the time interval 30 to 60 seconds? (A) 1.91×10-2 s-1 (B) 4.67×10-3 mol L-1 s-1 (C) 1.98×10-3 s-1 (D) 2.07×10-2 s-1

Tardigrade Admin · Accepted Answer

Average rate during the time interval 30-60 s. Rate=-(C2-C1/t2-t1) =-((0.17-0.31)/60-30) =(0.41/30) =4.67×10-3 mol L-1 s-1

Q. In a pseudo first order hydrolysis of ester in water, the following results were obtained.

t/s 0 30 60 90

Ester/mol $L^{- 1}$ 0.55 0.31 0.17 0.085

What will be the average rate of reaction between the time interval $30$ to $60$ seconds?

$1.91 \times 1 0^{- 2}$ $s^{- 1}$

$4.67 \times 1 0^{- 3} m o l L^{- 1} s^{- 1}$

$1.98 \times 1 0^{- 3}$ $s^{- 1}$

$2.07 \times 1 0^{- 2}$ $s^{- 1}$

Average rate during the time interval $30 - 60 s$ .
Rate= $- \frac{C _{2} - C _{1}}{t _{2} - t _{1}}$ $= - \frac{( 0.17 - 0.31 )}{60 - 30}$ $= \frac{0.41}{30}$
$= 4.67 \times 1 0^{- 3}$ $m o l L^{- 1}$ $s^{- 1}$

Q. In a pseudo first order hydrolysis of ester in water, the following results were obtained. t/s 0 30 60 90 Ester/mol L−1 0.55 0.31 0.17 0.085 What will be the average rate of reaction between the time interval 30 to 60 seconds?

1.91×10−2 s−1

4.67×10−3molL−1s−1

1.98×10−3 s−1

2.07×10−2 s−1