In a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occurs ?

Question

In a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occurs ? (A) 60 cm (B) 21.6 cm (C) 64 cm (D) 62 cm

Tardigrade Admin · Accepted Answer

Potential gradient =(1.5/36) [Initially] Finally (2.5/I2)=(1.5/36) ⇒ I 2=(36 × 2.5/1.5)=60 cm

Q. In a potentiometer circuit a cell of EMF $1.5 V$ gives balance point at $36 c m$ length of wire. If another cell of EMF $2.5 V$ replaces the first cell, then at what length of the wire, the balance point occurs ?

60 cm

21.6 cm

64 cm

62 cm

Potential gradient $= \frac{1.5}{36}$ [Initially]
Finally $\frac{2.5}{I _{2}} = \frac{1.5}{36}$
$\Rightarrow I_{2} = \frac{36 \times 2.5}{1.5} = 60 c m$

Q. In a potentiometer circuit a cell of EMF 1.5V gives balance point at 36cm length of wire. If another cell of EMF 2.5V replaces the first cell, then at what length of the wire, the balance point occurs ?