In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300nm to 400nm . Choose the closest value of change in the stopping potential from given options ((h c/e) = 1240 nm ⋅ V)

Question

In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300nm to 400nm . Choose the closest value of change in the stopping potential from given options ((h c/e) = 1240 nm ⋅ V) (A) 2.0V (B) 0.5V (C) 1.0V (D) 1.5V

Tardigrade Admin · Accepted Answer

vs1=(1240/300)-φ vs2=(1240/400)-φ vs1-vs2=(1240/300)-(1240/400) =4.13-3.1 =1.03 =1

Q. In a photoelectric experiment, the wavelength of the light incident on a metal is changed from $300 nm$ to $400 nm$ . Choose the closest value of change in the stopping potential from given options $(\frac{h c}{e} = 1240 nm \cdot V)$

$2.0 V$

$0.5 V$

$1.0 V$

$1.5 V$

$v_{s_{1}} = \frac{1240}{300} - ϕ$
$v_{s_{2}} = \frac{1240}{400} - ϕ$
$v_{s_{1}} - v_{s_{2}} = \frac{1240}{300} - \frac{1240}{400}$
$= 4.13 - 3.1$
$= 1.03$
$= 1$

Q. In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300nm to 400nm . Choose the closest value of change in the stopping potential from given options (ehc​=1240nm⋅V)

2.0V

0.5V

1.0V

1.5V